使用Python求解最小公倍数的方法

Python求最小公倍数

最小公倍数：两个或多个整数公有的倍数叫做它们的公倍数，其中除0以外最小的一个公倍数就叫做这几个整数的最小公倍数。整数a，b的最小公倍数记为[a，b]，同样的，a，b，c的最小公倍数记为[a，b，c]，多个整数的最小公倍数也有同样的记号。

利用Python求最小公倍数（4种方法）

算法一

# 算法1
def least_commo_multiple1():
    print("请输入3个数")
    x1 = int(input("请输入x1:"))
    x2 = int(input("请输入x2:"))
    x3 = int(input("请输入x3:"))
    x0 = max(x1,x2,x3)
    i = 1
    while(1):
        j = x0*i
        if j % x1==0 and j % x2 ==0 and j % 3 ==0:
            break
        i+=1
    print(x1,x2,x3,"这三个数的最小公倍数是：",j)

def max(x,y,z):
    if x>y and x>z:
        return x
    elif y>x and y>z:
        return y
    else:
        return z

算法二

# 算法2
def least_commo_multiple2():
    t=1
    print("请输入3个数")
    x1 = int(input("请输入x1:"))
    x = x1
    x2 = int(input("请输入x2:"))
    y = x2
    x3 = int(input("请输入x3:"))
    z = x3
    x0 = max(x1,x2,x3)
    for i in range(2,x0+1):
        flag = 1
        while flag:
            flag = 0
            if x1 % i == 0:
                x1 = x1 / i
                flag = 1
            if x2 % i == 0:
                x2 = x2 / i
                flag = 1
            if x3 % i == 0:
                x3 = x3 / i
                flag = 1
            if flag == 1:
                t = t * i
        x0 = max(x1,x2,x3)
    print(x, y, z, "这三个数的最小公倍数是：", t)

算法三

# 算法3
def least_commo_multiple3():
    print("请输入3个数")
    x1 = int(input("请输入x1:"))
    x2 = int(input("请输入x2:"))
    x3 = int(input("请输入x3:"))
    x0 = x1*x2/most_common_divisor(x1,x2)
    x0 = x0 * x3 / most_common_divisor(x0, x3)
    print(x1,x2,x3,"这三个数的最小公倍数是：",x0)

def most_common_divisor(a, b):
    c = a % b
    while c != 0:
        a = b
        b = c
        c = a % b
    return b

算法四

# 算法4
def least_commo_multiple4():
    print("请输入3个数")
    x1 = int(input("请输入x1:"))
    x2 = int(input("请输入x2:"))
    x3 = int(input("请输入x3:"))
    x0 = ff(ff(x1,x2),x3)
    print(x1, x2, x3, "这三个数的最小公倍数是：", x0)
def ff(a,b):
    a1 = a
    b1 = b
    c = a%b
    while c != 0:
        a = b
        b = c
        c = a%b
    return a1*b1/b

主函数

# 主函数
if __name__ == "__main__":
    # least_commo_multiple1()
    # least_commo_multiple2()
    # least_commo_multiple3()
    least_commo_multiple4()

效果截图：

以上就是Python语言求解三个数的最小公倍数啦~🤗