D*算法原理与程序详解(Python)

提示:前文写了D搜索算法,是一种贪心算法。

文章目录

  • 一、D*算法是什么?
  • 二、原理以及代码步骤
  • 1.原理分析
  • 2.代码解释
  • 总结

  • 一、D*算法是什么?

    D*算法也是用于机器人路径规划问题的启发式方法,它是一种局部规划方法,即仅仅已知一部分地形,对地形的未知部分进行假设,并在这些假设下找到当前坐标到目标坐标的最短路径。然后机器人沿着这条路走,当它观察到新的地图信息(如从前未知的障碍)时,将这些信息添加到地图中,并在必要时重新规划从当前坐标到给定目标坐标的新的最短路径。重复这个过程,直到达到目标坐标或无法达到目标坐标。

    二、原理以及代码步骤

    1.原理分析


    如上图的空间,给定起点(绿色点)、目标点(G蓝色)、障碍(红色),如何进行路径规划?

    1. 首次搜索
      将终点G置于openlist中,采用Dijkstra进行搜索,规定上下左右的代价为10,斜着方向的代价为14。不熟悉Dijkstra算法的朋友看我之前的博文Dijkstra算法在python中的实现
      大概说一下,每个格子包含有三个量(节点名,代价,父节点),从终点A开始,搜索周围的邻节点,给它们分别标号:B,C,D,E,F,代价按照规定的计算(上下左右的代价为10,斜着方向的代价为14),并把终点A放入close list里面(不再遍历)。然后找出代价最小的节点作为新节点,继续搜索,在搜索过程中,如果有节点K已经有代价,但是以新的点为父节点,这个节点K的代价值更小,那么更新其代价值和父节点。


      搜索结束条件就是终点从openlist中弹出进入了closelist。
      最终,我们搜索到了起点,结束搜索。从起点开始找父节点,一路搜索到终点。
    2. 遇到障碍
      如果机器人在按照原来规划路径行进的时候,路上遇到障碍(不在规划路径上的障碍忽略不计)。例如(3,3)遇到障碍。

      修改这个点的h值为无穷大(inf),并且令障碍的所有子节点的h都为无穷大。

      图中浅绿色节点是路径上障碍的子节点X,子节点X的h变为inf,将节点X从closelist中弹出,放入openlist列表。
      接下来就是将这个改变进行扩散。
      先取出openlist中k值最小的节点,还是浅绿色节点X(k=50,h=inf)
      找X的周围邻接点Y,如果能够让X的h值变小,就让Y成为X的父节点,这样X(3,2)的父节点变为(4,3),hx变为58,此时X的子节点如(3,1),而hx+10(x和y的代价)不等于hy(60),说明障碍的影响没有扩散到子节点,所以更改子节点(3,1)的h值为hx+10。
      因为(4,3)节点到目标点的路径其实是之前计算过的,所以不必计算。
      扩散的结束条件就是k_min(openlist中所有节点最小的k值)>=hx(当前点X的h值)。
      就能找到一条路径:

    2.代码解释

    1. D算法首次搜索
    # coding=utf-8
    import matplotlib.pyplot as plt
    import numpy as np
    import math
    
    map_grid = [[1 for j in range(0, 8)] for i in range(0, 8)]  # 定义列表
    map_grid = np.array(map_grid)  # 将列表转化为数组,因为只有数组才有维度的概念,方便切片
    map_grid[3:6, 1] = 0  # 障碍物
    map_grid[3:6, 5] = 0
    map_grid[0, 3] = 5  # 起点
    map_grid[7, 3] = 6  # 终点
    
    
    def draw_effect(map_grid,second_path):
        plt.imshow(map_grid, cmap=plt.cm.hot, interpolation='nearest', vmin=0, vmax=10)  # 绘制热力图
        plt.colorbar()
        plt.xlim(-1, 8)  # x轴的范围
        plt.ylim(-1, 8)
        my_x_ticks = np.arange(0, 8, 1)  # x轴标号的范围
        my_y_ticks = np.arange(0, 8, 1)
        plt.xticks(my_x_ticks)
        plt.yticks(my_y_ticks)
        second_path = np.array(second_path)
        plt.plot(second_path[:, 1:2],second_path[:, 0:1],'-')
        # plt.grid(True)  # 开启栅格  可以不开启
        plt.show()  # 可视化
    
    
    open_list = [[7, 3, 0, 0, None, None]]  # 将终点置于open列表中列表中分别有x0,y0坐标,h值,父节点X、Y坐标
    close_list = []
    
    
    # draw_effect(map_grid)
    # 将邻域放入open_list中
    def open_list_append(x0, y0, x1, y1, h0, h1, map_grid, open_list):
        if 0 <= x1 <= 7 and 0 <= y1 <= 7 and map_grid[x1, y1] != 4 and map_grid[x1, y1] != 0:  # 左边没有越界并且没有在closelist里面
            if map_grid[x1, y1] == 3:  # 如果是在open_list中,h要更新
                open_list = np.array(open_list)
                if (h1 + h0) < open_list[np.where((open_list[:, 0] == x1) & (open_list[:, 1] == y1)), 2]:
                    h = h1 + h0
                    k = h1 + h0
                    open_list[np.where((open_list[:, 0] == x1) & (open_list[:, 1] == y1)), 2] = h
                    open_list[np.where((open_list[:, 0] == x1) & (open_list[:, 1] == y1)), 3] = k
                    open_list[np.where((open_list[:, 0] == x1) & (open_list[:, 1] == y1)), 4] = x0
                    open_list[np.where((open_list[:, 0] == x1) & (open_list[:, 1] == y1)), 4] = y0
                open_list = list(open_list.tolist())
    
            else:  # 是new节点
                h = h1 + h0
                k = h1 + h0
                # open_list = list(open_list)
                open_list.append([x1, y1, h, k, x0, y0])
                map_grid[x1, y1] = 3
    
        return open_list
    
    
    # 首次搜索
    def first_search(open_list, close_list, map_grid):  # 给出终点坐标,完成首次遍历
        # 采用D算法遍历
        # 选openlist中h最小的,将openlist按照h排序,取第一个,并删除第一个,将它放到close_list里面
        open_list = list(open_list)
        open_list.sort(key=lambda x: x[2])
        # open_list.pop(0)
        insert_list = open_list[0]  # 引入中间列表,用来存储每一次被选中的遍历的点
        x0 = int(insert_list[0])
        y0 = int(insert_list[1])
        open_list.pop(0)
        close_list.append(list(insert_list))
        map_grid[x0, y0] = 4  # 被加入到close_list里面
    
        # 找insert_list的邻域 ----->寻找顺序:从左边开始逆时针
        h0 = int(insert_list[2])
    
        x1 = x0
        y1 = y0 - 1
        h1 = 10
        open_list = open_list_append(x0, y0, x1, y1, h0, h1, map_grid, open_list)
    
        x1 = x0 - 1
        y1 = y0 - 1
        h1 = 14
        open_list = open_list_append(x0, y0, x1, y1, h0, h1, map_grid, open_list)
    
        x1 = x0 - 1
        y1 = y0
        h1 = 10
        open_list = open_list_append(x0, y0, x1, y1, h0, h1, map_grid, open_list)
    
        x1 = x0 - 1
        y1 = y0 + 1
        h1 = 14
        open_list = open_list_append(x0, y0, x1, y1, h0, h1, map_grid, open_list)
    
        x1 = x0
        y1 = y0 + 1
        h1 = 10
        open_list = open_list_append(x0, y0, x1, y1, h0, h1, map_grid, open_list)
    
        x1 = x0 + 1
        y1 = y0 + 1
        h1 = 14
        open_list = open_list_append(x0, y0, x1, y1, h0, h1, map_grid, open_list)
    
        x1 = x0 + 1
        y1 = y0
        h1 = 10
        open_list = open_list_append(x0, y0, x1, y1, h0, h1, map_grid, open_list)
    
        x1 = x0 + 1
        y1 = y0 - 1
        h1 = 14
        open_list = open_list_append(x0, y0, x1, y1, h0, h1, map_grid, open_list)
    
        return [open_list, close_list, map_grid]
    
    
    while map_grid[0, 3] != 4 and open_list != []:
        [open_list, close_list, map_grid] = first_search(open_list, close_list, map_grid)
    
    # 首次搜索完成
    first_path = []
    close_list = np.array(close_list)
    xn = 0
    yn = 3
    while xn != 7 or yn != 3:
        list1 = list(close_list[np.where((close_list[:, 0] == xn) & (close_list[:, 1] == yn))][0])
        xn = int(list1[4])
        yn = int(list1[5])
        first_path.append(list1)
    
    first_path.append([7, 3, 0, 0, None, None])
    


    没开始搜索前的地图

    第一步搜索图
    第一步搜索图

    1. 设置随机障碍,开始第二次搜索
    # 通过上面的程序已经找到了一条路径,完成了第一次的搜索,此时每个节点的h和k是相等的。此时开始点在close list里面,最短路径在firstpath中。
    # 可以看出,每个节点的父节点都是该节点的八个邻节点中k值最小的哪个。
    # 当出现动态变化时,我们可以利用这个图尽快修正我们的路径,而不是重新规划。
    # 当我们检测到某点被阻碍了:1、修改这个点的h值,h变为inf,把它放入openlist中。注意此时该节点的k还是小值,是原来哪个h的值,因此它将立即被取出
    # 2、把这个修改扩散出去,直到kmin >=h
    # 设置一个突然出现的障碍
    map_grid[3, 3] = 0
    
    close_list[np.where((close_list[:, 4] == 3) & (close_list[:, 5] == 3)), 2] = math.inf
    close_list[np.where((close_list[:, 0] == 3) & (close_list[:, 1] == 3)), 2] = math.inf
    insertRow = list(close_list[np.where((close_list[:, 4] == 3) & (close_list[:, 5] == 3))][0])
    x = int(insertRow[0])
    y = int(insertRow[1])
    open_list.append(insertRow)  # ->>>>>>open_list是列表格式
    map_grid[x, y] = 3
    close_list = list(close_list.tolist())  # ----->>>>>close_list是列表格式
    close_list.remove(insertRow)
    open_list.sort(key=lambda x: x[3])  # 先排序,选择k最小的节点
    k_min = open_list[0][3]  #
    hx = open_list[0][2]
    
    
    # 接下来把这个点扩散出去
    
    def find_neighbor(x0, y0, x1, y1, k_old, hx, h1, close_list):
        close_list = np.array(close_list)
        hy = close_list[np.where((close_list[:, 0] == x1) & (close_list[:, 1] == y1)), 2][0]
        if (hy <= k_old) and (hx > hy + h1):
            close_list[np.where((close_list[:, 0] == x0) & (close_list[:, 1] == y0)), 4] = x1
            close_list[np.where((close_list[:, 0] == x0) & (close_list[:, 1] == y0)), 5] = y1
            close_list[np.where((close_list[:, 0] == x0) & (close_list[:, 1] == y0)), 2] = hy + h1
            hx = hy + h1
        return [hx, list(close_list.tolist())]
    
    def find_neighbor2(x0, y0, x1, y1, k_old, hx, h1, close_list, open_list, map_grid):
        close_list = np.array(close_list)
        hy = close_list[np.where((close_list[:, 0] == x1) & (close_list[:, 1] == y1)), 2][0]
        if (close_list[np.where((close_list[:, 0] == x1) & (close_list[:, 1] == y1)), 4] == x0 and close_list[
            np.where((close_list[:, 0] == x1) & (close_list[:, 1] == y1)), 5] == y0 and (hy != hx + h1)) or (
                (hy > hx + h1) and (
                (close_list[np.where((close_list[:, 0] == x1) & (close_list[:, 1] == y1)), 4] != x0) or (
                close_list[np.where((close_list[:, 0] == x1) & (close_list[:, 1] == y1)), 5] != y0))):
            close_list[np.where((close_list[:, 0] == x1) & (close_list[:, 1] == y1)), 4] = x0
            close_list[np.where((close_list[:, 0] == x1) & (close_list[:, 1] == y1)), 5] = y0
            close_list[np.where((close_list[:, 0] == x1) & (close_list[:, 1] == y1)), 2] = hx + h1
            Y = list(close_list[np.where((close_list[:, 0] == x1) & (close_list[:, 1] == y1))][0])
            # 把Y放入open_list中
            close_list = list(close_list.tolist())
            close_list.remove(Y)
            open_list.append(Y)
            map_grid[x1, y1] = 3
        return [open_list, close_list, map_grid]
    
    def find_neighbor3(x0, y0, x1, y1, k_old, hx, h1, close_list, open_list, map_grid):
        close_list = np.array(close_list)
        hy = close_list[np.where((close_list[:, 0] == x1) & (close_list[:, 1] == y1)), 2][0]
        if (close_list[np.where((close_list[:, 0] == x1) & (close_list[:, 1] == y1)), 4] == x0 and close_list[
            np.where((close_list[:, 0] == x1) & (close_list[:, 1] == y1)), 5] == y0 and (hy != hx + h1)):
            close_list[np.where((close_list[:, 0] == x1) & (close_list[:, 1] == y1)), 4] = x0
            close_list[np.where((close_list[:, 0] == x1) & (close_list[:, 1] == y1)), 5] = y0
            close_list[np.where((close_list[:, 0] == x1) & (close_list[:, 1] == y1)), 2] = hx + h1
            Y = list(close_list[np.where((close_list[:, 0] == x1) & (close_list[:, 1] == y1))][0])
            # 把Y放入open_list中
            close_list = list(close_list.tolist())
            close_list.remove(Y)
            open_list.append(Y)
            map_grid[x1, y1] = 3
        else:
            if ((close_list[np.where((close_list[:, 0] == x1) & (close_list[:, 1] == y1)), 4] != x0 or close_list[
                np.where((close_list[:, 0] == x1) & (close_list[:, 1] == y1)), 5] != y0) and (hy > hx + h1)):
                #print(list(close_list[np.where((close_list[:, 0] == x0) & (close_list[:, 1] == y0))][0]))
                if map_grid[x0,y0]!=3:
                    X = list(close_list[np.where((close_list[:, 0] == x0) & (close_list[:, 1] == y0))][0])
                    close_list = list(close_list.tolist())
                    close_list.remove(X)
                    open_list.append(X)
                else:
                    open_list = np.array(open_list)
                    X = list(open_list[np.where((open_list[:, 0] == x0) & (open_list[:, 1] == y0))][0])
                    open_list = list(open_list.tolist())
            #     # 把Y放入open_list中
                map_grid[x0, y0] = 3
            else:
                if ((close_list[np.where((close_list[:, 0] == x1) & (close_list[:, 1] == y1)), 4] != x0 or close_list[
                    np.where((close_list[:, 0] == x1) & (close_list[:, 1] == y1)), 5] != y0) and (hx > hy + h1)) and \
                        map_grid[x1, y1] == 4 and hy > k_old:
                    if map_grid[x1, y1] != 3:
                        Y = list(close_list[np.where((close_list[:, 0] == x1) & (close_list[:, 1] == y1))][0])
                        close_list = list(close_list.tolist())
                        close_list.remove(Y)
                        open_list.append(Y)
                    else:
                        open_list = np.array(open_list)
                        Y = list(open_list[np.where((open_list[:, 0] == x1) & (open_list[:, 1] == y1))][0])
                        open_list = list(open_list.tolist())
                    # 把Y放入open_list中
                    map_grid[x1, y1] = 3
    
        return [open_list, close_list, map_grid]
    
    # 扩散程序 process-state:先弹出openlist列表中k最小的节点,并删除这个节点。然后分类处理:
    def process_state(open_list, close_list, map_grid):
        # 修改这个点的h值
        open_list.sort(key=lambda x: x[3])  # 先排序,选择k最小的节点
        X = open_list[0]  # X表示k最小的节点
        x0 = int(X[0])
        y0 = int(X[1])
        close_list.append(X)  # 将它放入closelist
        map_grid[x0, y0] = 4
        open_list.remove(X)
        # 从openlist中删除这个节点
        # 分类处理:(该节点处于lower状态,该节点处于lower状态)
        k_old = X[3]
        hx = X[2]
        # print(close_list)
    
        if k_old < hx:  # k_old是上升状态
            x1 = x0
            y1 = y0 - 1
            h1 = 10
            [hx, close_list] = find_neighbor(x0, y0, x1, y1, k_old, hx, h1, close_list)
    
            x1 = x0 - 1
            y1 = y0 - 1
            h1 = 14
            [hx, close_list] = find_neighbor(x0, y0, x1, y1, k_old, hx, h1, close_list)
    
            x1 = x0 - 1
            y1 = y0
            h1 = 10
            [hx, close_list] = find_neighbor(x0, y0, x1, y1, k_old, hx, h1, close_list)
    
            x1 = x0 - 1
            y1 = y0 + 1
            h1 = 14
            [hx, close_list] = find_neighbor(x0, y0, x1, y1, k_old, hx, h1, close_list)
    
            x1 = x0
            y1 = y0 + 1
            h1 = 10
            [hx, close_list] = find_neighbor(x0, y0, x1, y1, k_old, hx, h1, close_list)
    
            x1 = x0 + 1
            y1 = y0 + 1
            h1 = 14
            [hx, close_list] = find_neighbor(x0, y0, x1, y1, k_old, hx, h1, close_list)
    
            x1 = x0 + 1
            y1 = y0
            h1 = 10
            [hx, close_list] = find_neighbor(x0, y0, x1, y1, k_old, hx, h1, close_list)
    
            x1 = x0 + 1
            y1 = y0 - 1
            h1 = 14
            [hx, close_list] = find_neighbor(x0, y0, x1, y1, k_old, hx, h1, close_list)
            # 找它的邻节点,看能不能让它的h降低
            #print(hx)
    
        # if k_old == hx:  # 该节点x处于lower状态
        #     x1 = x0
        #     y1 = y0 - 1
        #     h1 = 10
        #     [open_list, close_list, map_grid] = find_neighbor2(x0, y0, x1, y1, k_old, hx, h1, close_list, open_list,
        #                                                        map_grid)
        #
        #     x1 = x0 - 1
        #     y1 = y0 - 1
        #     h1 = 14
        #     [open_list, close_list, map_grid] = find_neighbor2(x0, y0, x1, y1, k_old, hx, h1, close_list, open_list,
        #                                                        map_grid)
        #
        #     x1 = x0 - 1
        #     y1 = y0
        #     h1 = 10
        #     [open_list, close_list, map_grid] = find_neighbor2(x0, y0, x1, y1, k_old, hx, h1, close_list, open_list,
        #                                                        map_grid)
        #
        #     x1 = x0 - 1
        #     y1 = y0 + 1
        #     h1 = 14
        #     [open_list, close_list, map_grid] = find_neighbor2(x0, y0, x1, y1, k_old, hx, h1, close_list, open_list,
        #                                                        map_grid)
        #
        #     x1 = x0
        #     y1 = y0 + 1
        #     h1 = 10
        #     [open_list, close_list, map_grid] = find_neighbor2(x0, y0, x1, y1, k_old, hx, h1, close_list, open_list,
        #                                                        map_grid)
        #
        #     x1 = x0 + 1
        #     y1 = y0 + 1
        #     h1 = 14
        #     [open_list, close_list, map_grid] = find_neighbor2(x0, y0, x1, y1, k_old, hx, h1, close_list, open_list,
        #                                                        map_grid)
        #
        #     x1 = x0 + 1
        #     y1 = y0
        #     h1 = 10
        #     [open_list, close_list, map_grid] = find_neighbor2(x0, y0, x1, y1, k_old, hx, h1, close_list, open_list,
        #                                                        map_grid)
        #
        #     x1 = x0 + 1
        #     y1 = y0 - 1
        #     h1 = 14
        #     [open_list, close_list, map_grid] = find_neighbor2(x0, y0, x1, y1, k_old, hx, h1, close_list, open_list,
        #                                                        map_grid)
        #
        # else:
        #     x1 = x0
        #     y1 = y0 - 1
        #     h1 = 10
        #     [open_list, close_list, map_grid] = find_neighbor3(x0, y0, x1, y1, k_old, hx, h1, close_list, open_list,
        #                                                        map_grid)
        #
        #     x1 = x0 - 1
        #     y1 = y0 - 1
        #     h1 = 14
        #     [open_list, close_list, map_grid] = find_neighbor3(x0, y0, x1, y1, k_old, hx, h1, close_list, open_list,
        #                                                        map_grid)
        #     #
        #     x1 = x0 - 1
        #     y1 = y0
        #     h1 = 10
        #     [open_list, close_list, map_grid] = find_neighbor3(x0, y0, x1, y1, k_old, hx, h1, close_list, open_list,
        #                                                        map_grid)
        #     #
        #     x1 = x0 - 1
        #     y1 = y0 + 1
        #     h1 = 14
        #     [open_list, close_list, map_grid] = find_neighbor3(x0, y0, x1, y1, k_old, hx, h1, close_list, open_list,
        #                                                        map_grid)
        #     #
        #     x1 = x0
        #     y1 = y0 + 1
        #     h1 = 10
        #     [open_list, close_list, map_grid] = find_neighbor3(x0, y0, x1, y1, k_old, hx, h1, close_list, open_list,
        #                                                        map_grid)
        #     x1 = x0 + 1
        #     y1 = y0 + 1
        #     h1 = 14
        #     [open_list, close_list, map_grid] = find_neighbor3(x0, y0, x1, y1, k_old, hx, h1, close_list, open_list,
        #                                                        map_grid)
        #
        #     x1 = x0 + 1
        #     y1 = y0
        #     h1 = 10
        #     [open_list, close_list, map_grid] = find_neighbor3(x0, y0, x1, y1, k_old, hx, h1, close_list, open_list,
        #                                                        map_grid)
        #     x1 = x0 + 1
        #     y1 = y0 - 1
        #     h1 = 14
        #     [open_list, close_list, map_grid] = find_neighbor3(x0, y0, x1, y1, k_old, hx, h1, close_list, open_list,
        #                                                    map_grid)
    
        open_list.sort(key=lambda x: x[3])  # 先排序,选择k最小的节点
        k_min = open_list[0][3]  #
    
        return [open_list, list(close_list), map_grid,k_min,hx]
    
    while k_min<hx:
        [open_list, close_list, map_grid,k_min,hx] = process_state(open_list, close_list, map_grid)
    
    
    #避障
    second_path = []
    close_list = np.array(close_list)
    xn = 0
    yn = 3
    while xn != 7 or yn != 3:
        list1 = list(close_list[np.where((close_list[:, 0] == xn) & (close_list[:, 1] == yn))][0])
        xn = int(list1[4])
        yn = int(list1[5])
        second_path.append(list1)
    
    second_path.append([7, 3, 0, 0, None, None])
    draw_effect(map_grid,second_path)
    print("Find it")
    


    完成第二次搜索图。


    总结

    D* 算法融合了D算法和A* 算法,可以处理局部动态障碍,运算速度很快。
    原本的伪代码是这样的,我根据我地图的实际情况进行了改变。

    k_old<h(x): 当前h(x)升高说明原来的路径已经不是最优的了,如果在x周围能找到一个点,h.y+c(x,y)更小,那就修改x的父节点,重置其h的值。

    k_old=h(x): 它的父节点是X,但是h.y却不等, 设想一下说明这说明h.y被更改了,但是父节点还没有变。

    参考原文链接:D*规划算法及python实现

    来源:问题很多de流星

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